x^2+0.1212x-0.0018=0

Solution for x^2+0.1212x-0.0018=0 equation:

x^2+0.1212x-0.0018=0

a = 1; b = 0.1212; c = -0.0018;
Δ = b2-4ac
Δ = 0.12122-4·1·(-0.0018)
Δ = 0.02188944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.1212)-\sqrt{0.02188944}}{2*1}=\frac{-0.1212-\sqrt{0.02188944}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.1212)+\sqrt{0.02188944}}{2*1}=\frac{-0.1212+\sqrt{0.02188944}}{2}
$